- Given a binary tree, calculate non-leaves having left & right child nodes in a binary tree.
- Count non leaf nodes having both children.
- We will iterate the binary tree using level order traversal or breadth first search (BFS) traversal.
- We have already discussed:
- Count non leaf nodes in a binary tree having one child (Either left child or right child).
- Count non leaf nodes in a binary tree (having one child or both children).
Examples: Count non leaf nodes in a binary tree
Example 1: Number of non leaf nodes in binary tree (left & right children).
Given a binary tree shown in Fig 1, calculate the number of non leaf nodes having left & right child nodes.
- Traverse the binary tree using level order traversal algorithm.
- At each node check the reference of left & right node.
- If current node have non null left & right node
- Increment the count of leaf nodes.
- Else, keep on traversing the binary tree.
- If current node have non null left & right node
- We will have following conditional statement to cater this case.
if( node.left != null && node.right != null) {
nNonLeaves++;
}
Example 2: Count non leaf nodes having left & right child (Fig 2).
- Traverse binary tree using breadth first search.
- Declare a variable nLeaves = 0
- During iteration check, current node has both left & right child.
- nLeaves ++ (if nodes have both left & right child).
- At the end of iteration, we will number of non leaf nodes having left & right child node.
- Number of non leaf nodes of binary tree is 5.
Time complexity of algorithm is O(n).
Program – count non leaf nodes in a binary tree using java
1.) CountNonLeafTwoChildren class:
- CountNonLeafTwoChildren class is responsible to calculate the number of non leaf nodes in a binary tree.
package org.learn.Question;
import java.util.LinkedList;
import java.util.Queue;
public class CountNonLeafNodes {
public static int countNonLeafNodes(Node root) {
if (root == null) {
System.out.println("Tree is empty");
return -1;
}
int nNonLeaves = 0;
Queue<Node> queue = new LinkedList<Node>();
queue.offer(root);
while (!queue.isEmpty()) {
Node node = queue.poll();
if (node.left != null && node.right != null) {
nNonLeaves++;
}
if (node.left != null) {
queue.offer(node.left);
}
if (node.right != null) {
queue.offer(node.right);
}
}
System.out.println("Number of non-leaf nodes : " + nNonLeaves);
return nNonLeaves;
}
}
2.) Node class:
- Node class represents the nodes of a binary tree.
package org.learn.Question;
public class Node {
public int data;
public Node left;
public Node right;
public Node(int num) {
this.data = num;
this.left = null;
this.right = null;
}
public Node() {
this.left = null;
this.right = null;
}
public static Node createNode(int number) {
return new Node(number);
}
}
3.) App Class:
- We are creating a binary tree in main method.
- We are calling CountNonLeafTwoChildren class, to calculate number of non leaf nodes using level order traversal.
package org.learn.Client;
import org.learn.Question.CountNonLeafNodes;
import org.learn.Question.Node;
public class App {
public static void main(String[] args) {
// root level 0
Node A = Node.createNode(55);
// Level 1
Node B = Node.createNode(50);
Node C = Node.createNode(40);
// Level 2
Node D = Node.createNode(25);
Node E = Node.createNode(80);
Node F = Node.createNode(45);
Node G = Node.createNode(90);
// Level 3
Node H = Node.createNode(10);
Node I = Node.createNode(35);
Node J = Node.createNode(65);
Node K = Node.createNode(75);
// connect Level 0 and 1
A.left = B;
A.right = C;
// connect level 1 and level 2
B.left = D;
B.right = E;
C.left = F;
C.right = G;
// connect level 2 and level 3
F.left = H;
F.right = I;
G.left = J;
G.right = K;
CountNonLeafNodes.countNonLeafNodes(A);
}
}
Output – count non leaf nodes having left & right child nodes in java
Number of non-leaf nodes : 5
Download Code – Count Non Leaf nodes Binary Tree
